60-30-90 triangle

[K‡rbyroth]

I need help i dont know what i did wrong

I given the short leg measure as 10 so that means the hypotenuse should be 20. I need to figure out the long leg.

a^2 + b^2 = C^2
a^2 + 10^2 = 20^2
a^2 + 100 = 400
a^2= 400 - 100
a^2 = 300
a = sqroot of 300

I given 4 possible answers. I dont see how any of them are right

5sqroot3
10sqroot3
20
10sqroot2

 

[Deleted member 4993]

I need help i dont know what i did wrong

I given the short leg measure as 10 so that means the hypotenuse should be 20. I need to figure out the long leg.

a^2 + b^2 = C^2
a^2 + 10^2 = 20^2
a^2 + 100 = 400
a^2= 400 - 100
a^2 = 300
a = sqroot of 300...... = \(\displaystyle \sqrt{100\times 3} \, = \, \sqrt{100} \, \times \sqrt{3} \, = \, 10 \, \times \sqrt{3} \,\)

I given 4 possible answers. I dont see how any of them are right

5sqroot3
10sqroot3
20
10sqroot2

 

[K‡rbyroth]

oh wow thanks this stuff gets confusing