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Thread: dy/dx=x+y

  1. #1


    Find y0 so that the integral curve for dy/dx=x+y y(-4)=y0 is a straight line. You must justify your answer, which will require you to apply algebraic reasoning to the problem.

    I know the answer is 3. I also know this differential equation looks simple, but I can't get the starting equation separated. We are studying separable equations so I must do it using that method. If someone could help me get it separated I think I can handle it. Thank you.

  2. #2
    Elite Member
    Join Date
    Apr 2005
    I'm feeling an urge to do a change of variables: y = t*x

  3. #3
    Firstly, the DE y' = x + y can be solved like such:
    Multiply by e-x: e-xy' - e-xy = xe-x

    Integrate: e-xy = -e-x(x+1) + c1

    Solve; divide by e-x: y(x) = c1ex - x - 1

    Secondly, solve for c1.

    IVP: y(-4) = y0 = c1e-4 + 3

    Solve: c1 = (y0 - 3)e4

    Input: y(x) = (y0 - 3)ex+4 - x - 1

    When y0 - 3, the equation is y(x) = -x - 1.

    This can be reasoned as the only solution because while y = -x - 1 by definition a strait line, y=cex+4 is not a strait line except at c=0. There are, of course, other mathematical ways of proving this.


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