I have a question:
For the quadratic equation (2x+1)(x+3)=0, does 2=a, 1=b, and 3=c?
I have a question:
For the quadratic equation (2x+1)(x+3)=0, does 2=a, 1=b, and 3=c?
Last edited by mmm4444bot; 07-20-2012 at 08:04 PM. Reason: Title typo, title typo, title typo
Last edited by srmichael; 07-20-2012 at 03:36 PM.
"There are 10 types of people in this world - those who understand binary and those who don't."
You mean multiply?
Of course he means multiply! Have you not learned FOIL yet?!
PS: I split your previous thread. Note the useful subject line.
What grade are you in now?
Okay, I did the FOIL method, and got:
2x^{2}+7x+3
2=a,7=b, and 3=c
Right? Please say yes.
Yes.
Are you thinking that you need to use the Quadratic Formula to solve the equation (2x+1)(x+3) = 0 ?
If so, I would like you to know that there is a much simpler method that uses something called the Zero-Product Property.
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