ok. Vector space apart if we consider vector with direction and think it graphically,that is it has an initial and terminal point then how can you define the condition of equality?
Vectors are not physical objects. Learn that!
Many physical objects, real world ideas, scientific concepts can be represented as a vector. But a vector itself is none of those things. It is a number triple if we are in 3space.
In your example, suppose there are points, \(\displaystyle P: (1,-2,0)~\&~Q: (3,4,-1)\).
We often say the \(\displaystyle <2,6,-1>\) represents the 'action' of 'moving' from \(\displaystyle P\text{ to Q}.\)
We even symbolize it as \(\displaystyle \overrightarrow {PQ} \).
BUT the vector \(\displaystyle <2,6,-1>\) also symbolizes going from point \(\displaystyle A: (-7,2,5)\) to point \(\displaystyle B: (-5,8,4)\).
Now quite clearly \(\displaystyle A\ne P~\&~B\ne Q\), but nevertheless \(\displaystyle \overrightarrow {PQ}=\overrightarrow {AB}=<2,6,-1>\)
Many good textbooks on vectors stress the point that we can
think of vectors as having length & direction.
Now they do that even though in the mathematics of 3space,
a vector is a number triple.