Would
Cos(θ-π)sin(θ+π)
Simplify to 1/2[sin2θ+sin2π]
Or would you have to continue to simplify sin 2π to 0 and end up with 1/2[sin2θ] Sinθ?..............where did that come from?
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.