hopelynnwelch
Junior Member
- Joined
- Jan 16, 2015
- Messages
- 60
I have had no problems doing these until there are SQRTs involved.
The limit as x goes to 6 from the negative side of (sqrt(6-x))/(6-x)
I'm trying this again and if I multiply this function by (sqrt(6-x))/(sqrt(6-x)) and don't multiply out the denominator and then cancel I get
1/(sqrt(6-x))
This is undefined at 6 because 1/0 is undefined...
What did I miss here?
I should edit this to add that I know the limit is INFINITY. But how the heck can I come to this conclusion algebraically?
The limit as x goes to 6 from the negative side of (sqrt(6-x))/(6-x)
I'm trying this again and if I multiply this function by (sqrt(6-x))/(sqrt(6-x)) and don't multiply out the denominator and then cancel I get
1/(sqrt(6-x))
This is undefined at 6 because 1/0 is undefined...
What did I miss here?
I should edit this to add that I know the limit is INFINITY. But how the heck can I come to this conclusion algebraically?
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