OK - the height is measured from the bottom of the sphere and you got the proper radius r
r2 = 22 - (2-h)2 = 4h - h2,
and the proper cross sectional area. You are now at
\(\displaystyle \pi\) (4h - h2) h' = -a \(\displaystyle \sqrt{20\, h}\)
a is just the cross sectional area of the hole but you have to be careful about the units. Since h is in meters, we should have the radius of the hole in meters also. Note that 1 meter is 100 cm.
No. But you are correct in that the radius of the hole is 0.01 m. However, a is the area of the hole, not the radius. What is the area of a circle with 0.01 m radiusso would the final equation be (4h-h^2)h'=0.01/pi square 20h
Isn't that the answer you were looking for?it would be pir^2 which the pi would cancel out and it would -0.0001
Go back and read the problemso after we find a which is (4h-h2)h'=-0.0001sqaured20h would you have to take the derivative in order to solve for b which is "how long will it take for the water to completely drains? the reason im asking it doesnt give you the time so would it be 0 because im confused on how to start it and dont know where to begin
Yes, it does. You now have the formulasi still dont understand does it have something to do with in the begin of the problem
disregard the question about 3 sorry i have another question about 4 that is im different and my equation look like these
(4h-h2)(20h)-1/2=-0.0001t+C
we Distributive the 20h square correct and i already know what the t is 0 and h=2.