Hi everyone. My question is:
Given l= {(x,y,z) = (x-1)/2 = (y+2)/-1 = z/3 }
find a line l' through (1,2,3) such that l and l' are skew.
I know that P(-1,+2,0) and u=(2,-1,3)
However, I do not know that direction vector (u) of l'.
If l and l' are skew, then l ∩ l' = ø and they are not parallel. So what? How can I find the direction vector of l'?
Given l= {(x,y,z) = (x-1)/2 = (y+2)/-1 = z/3 }
find a line l' through (1,2,3) such that l and l' are skew.
I know that P(-1,+2,0) and u=(2,-1,3)
However, I do not know that direction vector (u) of l'.
If l and l' are skew, then l ∩ l' = ø and they are not parallel. So what? How can I find the direction vector of l'?