Hi,
I came across this question , while going through the fractions chapter.Can anyone help me in how to approach and solve the problem (1) in a better way?
5. Find out the missing figures (denoted by stars) in the following equations, the fractions being given in their lowest terms:
. . .\(\displaystyle \mbox{i) }\, *\, \dfrac{3}{7}\, \times\, 2\, \dfrac{3}{*}\, =\, 14\, \dfrac{*}{14}\)
. . .\(\displaystyle \mbox{ii) }\, 7\, \dfrac{*}{3}\, -\, *\, \dfrac{5}{11}\, =\, 3\, \dfrac{*}{*3}\)
. . .\(\displaystyle \mbox{iii) }\, 8\, \dfrac{9}{**}\, \div\, *\, \dfrac{2}{27}\, =\, 7\, \dfrac{16}{17}\)
. . .\(\displaystyle \mbox{iv) }\, 2\, \dfrac{1}{2}\, -\, 3\, \dfrac{2}{3}\, +\, 1\, \dfrac{5}{6}\, -\, \dfrac{2}{*}\, =\, 0\)
. . .\(\displaystyle \mbox{v) }\, \dfrac{1}{2\,\dfrac{3}{4}}\, +\, \dfrac{1}{5\, \dfrac{1}{5}}\, +\, \dfrac{1}{*}\, +\, \dfrac{1}{9\, \dfrac{8}{15}}\, =\, \dfrac{144}{143}\)
Edit 1:
I have started the problem by replacing the asterisk sign by variables x,y,z.And I have found the missing denominator in the mixed fraction ( 2+ 3/* ) to be 4 as (LCM of 7,4,14 will be 28).Kindly let me know whether the approach is correct or not.
Ty.
I came across this question , while going through the fractions chapter.Can anyone help me in how to approach and solve the problem (1) in a better way?
5. Find out the missing figures (denoted by stars) in the following equations, the fractions being given in their lowest terms:
. . .\(\displaystyle \mbox{i) }\, *\, \dfrac{3}{7}\, \times\, 2\, \dfrac{3}{*}\, =\, 14\, \dfrac{*}{14}\)
. . .\(\displaystyle \mbox{ii) }\, 7\, \dfrac{*}{3}\, -\, *\, \dfrac{5}{11}\, =\, 3\, \dfrac{*}{*3}\)
. . .\(\displaystyle \mbox{iii) }\, 8\, \dfrac{9}{**}\, \div\, *\, \dfrac{2}{27}\, =\, 7\, \dfrac{16}{17}\)
. . .\(\displaystyle \mbox{iv) }\, 2\, \dfrac{1}{2}\, -\, 3\, \dfrac{2}{3}\, +\, 1\, \dfrac{5}{6}\, -\, \dfrac{2}{*}\, =\, 0\)
. . .\(\displaystyle \mbox{v) }\, \dfrac{1}{2\,\dfrac{3}{4}}\, +\, \dfrac{1}{5\, \dfrac{1}{5}}\, +\, \dfrac{1}{*}\, +\, \dfrac{1}{9\, \dfrac{8}{15}}\, =\, \dfrac{144}{143}\)
Edit 1:
I have started the problem by replacing the asterisk sign by variables x,y,z.And I have found the missing denominator in the mixed fraction ( 2+ 3/* ) to be 4 as (LCM of 7,4,14 will be 28).Kindly let me know whether the approach is correct or not.
Ty.
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