A binomial factor: w(w + 2)^2 + 8(w + 2)^2

cgarcia71

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Mar 18, 2006
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I am stumped on the following problem. Ineed to factor out the GCF.

w(w+2)^2 + 8(w+2)^2

I can see that the GCF is w+2

normally I know that I would solve like this

(w+2)w+(w+2)8 = (w+2)(w+8)

The exponents are throwing me off though. I can't seem to find an example that helps me understand that. Can someone help?

Thanks in advance!
 
Sometimes, you just have to see it.

(w+8)*(w+2)<sup>2</sup>
 
cgarcia71 said:
I am stumped on the following problem. Ineed to factor out the GCF.

w(w+2)^2 + 8(w+2)^2

I can see that the GCF is w+2

normally I know that I would solve like this

(w+2)w+(w+2)8 = (w+2)(w+8)

The exponents are throwing me off though. I can't seem to find an example that helps me understand that. Can someone help?

Thanks in advance!

If you had been asked to factor
w k<sup>2</sup>+ 8 k<sup>2</sup>

would you have "seen" that the factorization is
k<sup>2</sup> (w + 8)

Now, is your problem all that much different than this?
 
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