A cone and cylinder are joined to make a solid. (The cone is on top of the cylinder.)

[guy]

How would you solve this
I just want to understand the process as i am not getting to it

 

[stapel]

Question 7: A cone and cylinder are joined to make a solid. The radius of each is [imath]r[/imath]. The height of the cylinder is [imath]r + 6[/imath]. The slant height of the cone is [imath]\frac{3r}{2}[/imath].

Show the total surface area of the solid is [imath]\frac{3\pi r}{2}(3r + 8)[/imath]

How would you solve this
I just want to understand the process as i am not getting to it

Process:

a) What is the formula for the surface area of a cone with the given dimensions?

b) What is the formula for the surface area of a cylinder with the given dimensions?

c) Which surface of the cone and the cylinder should *not* be counted either time for this particular solid?

d) After subtracting, what is the resulting surface area?

 

[Dr.Peterson]

View attachment 36571How would you solve this
I just want to understand the process as i am not getting to it

Alternatively, you can think separately about the lateral surface of the cone, the lateral surface of the cylinder, and the base of the cylinder. Just add those up, and simplify.

What formulas have you learned for surface areas?

Then show us any work you have tried, so we can see what additional help you need.