A graphing question

[bigmama]

How would I graph this 2x+3y=6

 

[skeeter]

2x + 3y = 6

let x = 0 ... y = 2, so the point (0,2) is on the line

let y = 0 ... x = 3, so the point (3,0) is on the line

plot the two points on a Cartesian grid and draw the line.

 

[jonboy]

Skeeter's method is perfect.

There's also another way.

Change $\displaystyle 2x\,+\,3y\,=\,6$ in $\displaystyle y\,=\,mx\,+\,b$

So:\(\displaystyle \L \;\;2x\,+\,3y\,=\,6\;\;\Rightarrow\;\;y\,=\,-\,\frac{2}{3}\,+\,2\).

Graph the y - intercept that you know:$\displaystyle \;(0\,,\,2)$

Now since slope is $\displaystyle \,\frac{rise}{run}\,$ we have two choices to plot points:

...Move repeatedly up 2 units and then down 3 units from $\displaystyle \;(0\,,\,2)$

...Move repeatedly down 2 units and then up 3 units from $\displaystyle \;(0\,,\,2)$

So you should get:

 

[bigmama]

Thank both of you very much. I'm not good at math.[/b]