The Student
Junior Member
- Joined
- Apr 25, 2012
- Messages
- 241
Question: Let z, be an arbitrary complex number. Show z =
if and only if z ∈ R. Here's how I am attempting to solve this. Let
be the complex conjugate of z = a + bi. So if z must be real, then z = a + b, and
= a - bi. a + b = a - bi; b = bi; b^2 = - b^2. I must be misunderstanding what the question is looking for; does anyone have any ideas?