addition: x / x - 1 + 1 / x

[BB]

Please help with this addition problem
x/x-1 + 1/x

This is what i have so far is this accurate
x+1/x(x-1) = x+1/x-1

 

[jwpaine]

You did your common denominator correctly, but your numerator is going to be
(x*x) + (x-1)

 

[BB]

Thank you for the help
So my problem should read

x/x-1 + 1/x

x+x/x(x-1) + x-1/x-1

 

[jwpaine]

\(\displaystyle \L \frac{x}{x+1} \,+\, \frac{1}{x}\,\,=\,\, \frac{x \cdot x\,+\,1(x-1)}{x(x-1)} = \frac{x^2\,+\,x-1}{x(x-1)}\)

You could go even further with polynomial long division...if you're doing that.

Cheers,
John