algebra: A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each.

[diksha]

A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is

 

[stapel]

Your post has now been split from the other student's. In future, kindly please post your own questions as "new" topics, rather than as hijacks of others' topics.

A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is

What are your thoughts? What have you tried? How far have you gotten? Where are you stuck?

For instance, you noted that eight watermelon would be too many, as would be six pineapples. But one of each would be too few. So, within those parameters, you could try various combinations. So you tried... what?

Please be complete. Thank you!