Algebra (College freshman)

Try bringing out (x-7) from 6xy^2 - 42y^2 and from - 4x + 28.

Factor by grouping. You could probably pull out a 2 too.
 
\(\displaystyle 6xy^2 \, - \, 42y^2 \, - 4x \, + \, 28\)

Bring out (x-7) in the first half:
\(\displaystyle 6xy^2 \, - \, 42y \, = \, 6y^2(x - 7)\)

Bring out (x-7) in the second half:
- 4x + 28 = -4(x - 7)

So we have
\(\displaystyle 6y^2(x - 7) \, - \, 4(x - 7)\)

Easier example:

6b(a) - 4(a) = (6b - 4)a, right?

Can you proceed?

(Yes, Denis, we'll bring out the 2!!!)
 
"factor completely 6xy^2 - 42y^2 - 4x + 28"

Well, why not eliminate that annoying "2" right off the bat; divide by 2:
3xy^2 - 21y^2 - 2x + 14

Now start your pulling out process :idea:
 
I think I made reference to you saying just that.
 
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