Algebra Help: simplify {54 b^4 x^4 / 16 b x^2}^1/3
- Thread starter Matholdie
- Start date
skeeter
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- Dec 15, 2005
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\(\displaystyle [\frac {54b^4x^4}{16bx^2}]^{\frac{1}{3}}\)
reduce the fraction inside the brackets first ...
\(\displaystyle [\frac {27b^3x^2}{8}]^{\frac{1}{3}}\)
raise every term to the 1/3 power ...
\(\displaystyle \frac{27^{\frac{1}{3}}(b^3)^{\frac{1}{3}}(x^2)^{\frac{1}{3}}}{8^{\frac{1}{3}}}\)
simplify ...
\(\displaystyle \frac{3b \sqrt[3]{x^2}}{2}\)
reduce the fraction inside the brackets first ...
\(\displaystyle [\frac {27b^3x^2}{8}]^{\frac{1}{3}}\)
raise every term to the 1/3 power ...
\(\displaystyle \frac{27^{\frac{1}{3}}(b^3)^{\frac{1}{3}}(x^2)^{\frac{1}{3}}}{8^{\frac{1}{3}}}\)
simplify ...
\(\displaystyle \frac{3b \sqrt[3]{x^2}}{2}\)
