Algebra

kk12

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Sep 2, 2010
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If v and x are positive integers such that v=(7/3)b and b=(x^2)/2, what is the least possible value of v?
 


Substitute x^2/2 for b in the expression for v, and simplify.

This will give you an expression for v in terms of x.

To find the smallest possible value for this expression, substitute the smallest positive integer for x, and simplify again.

Please show your work, or ask specific questions, if you need more help.

Cheers ~ Mark 8-)

 
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