K kk12 New member Joined Sep 2, 2010 Messages 1 Sep 2, 2010 #1 If v and x are positive integers such that v=(7/3)b and b=(x^2)/2, what is the least possible value of v?
If v and x are positive integers such that v=(7/3)b and b=(x^2)/2, what is the least possible value of v?
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Sep 2, 2010 #2 Substitute x^2/2 for b in the expression for v, and simplify. This will give you an expression for v in terms of x. To find the smallest possible value for this expression, substitute the smallest positive integer for x, and simplify again. Please show your work, or ask specific questions, if you need more help. Cheers ~ Mark
Substitute x^2/2 for b in the expression for v, and simplify. This will give you an expression for v in terms of x. To find the smallest possible value for this expression, substitute the smallest positive integer for x, and simplify again. Please show your work, or ask specific questions, if you need more help. Cheers ~ Mark