vito_corleone
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- Nov 26, 2016
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A dartboard is in the shape of an equilateral triangle inside which is inscribed a circle.
A dart is randomly thrown at the board (Assume that it hits the board).
Given that tan 60° = sqrt(3) , and sin 60° = sqrt(3)/2, show that the probability of the dart hitting the board inside the circle is π/ 3* sqrt(3).
The probability should be the area of the circle divided by the area of the triangle , and you should end up with π/ 3* sqrt(3).
But how do you end up with that starting from scratch, as I end up with a different answer , when I solve it?
Thanks in advance.
The diagram given looks like this :- http://tinyurl.com/3nym92q
A dart is randomly thrown at the board (Assume that it hits the board).
Given that tan 60° = sqrt(3) , and sin 60° = sqrt(3)/2, show that the probability of the dart hitting the board inside the circle is π/ 3* sqrt(3).
The probability should be the area of the circle divided by the area of the triangle , and you should end up with π/ 3* sqrt(3).
But how do you end up with that starting from scratch, as I end up with a different answer , when I solve it?
Thanks in advance.
The diagram given looks like this :- http://tinyurl.com/3nym92q