keri__lynn
New member
- Joined
- Jul 7, 2008
- Messages
- 9
Here is my question
it says Two boats are observed by a parasailer 75 meters above a lake. The angles of depression are 12.5 degrees and 7 degrees. How far apart are the boats?
Here is an example i have to go by i did work this problem out like this example but i got the wrong answer... can you please show me how to work this problem out step by step....
The example given is indrect measurement
Olivia is in a lighthouse on a cliff. She observes two sailboats due east of the lighthouse. The angles of depression to the two boats are 33 degrees and 57 degrees. Find the distance between the two sailboats to the nearest foot.
triangle CDA and CDB are right triangles and CD = 110 + 85 or 195. The distance between the boats is AB or BD - AD. Use the right traingles to find these two lenths.
Because CE and DB are horizontal lines, they are parallel. Thus <ECB = <CBD and <ECA = <CAD because they are alternate interior angles. This means that m<CBD = 33 and m<CAD = 57.
tan 33 degrees = 195 / DB
DB tan 33 = 195
DB = 195 / tan 33
DB = 300.27
tan 57 = 195 / DA
DA tan 57 = 195
DA = 195 / tan 57
DA = 126.63
the distance between the boats is DB - DA.
DB - DA = 300.27 - 126.63 or about 174 feet
it says Two boats are observed by a parasailer 75 meters above a lake. The angles of depression are 12.5 degrees and 7 degrees. How far apart are the boats?
Here is an example i have to go by i did work this problem out like this example but i got the wrong answer... can you please show me how to work this problem out step by step....
The example given is indrect measurement
Olivia is in a lighthouse on a cliff. She observes two sailboats due east of the lighthouse. The angles of depression to the two boats are 33 degrees and 57 degrees. Find the distance between the two sailboats to the nearest foot.
triangle CDA and CDB are right triangles and CD = 110 + 85 or 195. The distance between the boats is AB or BD - AD. Use the right traingles to find these two lenths.
Because CE and DB are horizontal lines, they are parallel. Thus <ECB = <CBD and <ECA = <CAD because they are alternate interior angles. This means that m<CBD = 33 and m<CAD = 57.
tan 33 degrees = 195 / DB
DB tan 33 = 195
DB = 195 / tan 33
DB = 300.27
tan 57 = 195 / DA
DA tan 57 = 195
DA = 195 / tan 57
DA = 126.63
the distance between the boats is DB - DA.
DB - DA = 300.27 - 126.63 or about 174 feet