renegade05
Full Member
- Joined
- Sep 10, 2010
- Messages
- 260
Question: Using proper set notation, describe the domain of \(\displaystyle f(x,y)=cose^{-1}(2x^2+y^2-3)\). What is the domain, what is the range of \(\displaystyle f\)?
So, I started off with realizing that \(\displaystyle 2x^2+y^2-3\) has to be between -1 and 1. Or equal to -1 or 1.
So, how do I go about doing this one? Solve the inequality? \(\displaystyle -1<=2x^2+y^2-3<=1\) ? And then what?
And isn't the range just between 0 and \(\displaystyle \pi\) ?
Little help..
So, I started off with realizing that \(\displaystyle 2x^2+y^2-3\) has to be between -1 and 1. Or equal to -1 or 1.
So, how do I go about doing this one? Solve the inequality? \(\displaystyle -1<=2x^2+y^2-3<=1\) ? And then what?
And isn't the range just between 0 and \(\displaystyle \pi\) ?
Little help..