Looking at the same one from the other thread:
\(\displaystyle \dfrac{2\sqrt{x}}{dx} = \dfrac{\sqrt{1 - y^{2}}}{dy}\)
\(\displaystyle \dfrac{2dy }{(1 - y^{2})^{1/2}} = x^{-1/2}dx \)
\(\displaystyle 2\int \dfrac{dy}{(1 - y^{2})^{1/2}} = \int x^{-1/2}dx\) Did the 2 on the far left side come from substitution?
\(\displaystyle 2 \arcsin y + C_y = 2x^{1/2} + C_x\)
\(\displaystyle 2 \arcsin y + C_y - C_y - = 2x^{1/2} + C_x - C_y\)
\(\displaystyle 2 \arcsin y = 2x^{1/2} + C\)
\(\displaystyle \arcsin y = x^{1/2} + C\)
\(\displaystyle y = \sin(\sqrt{x} + C)\)
\(\displaystyle \dfrac{2\sqrt{x}}{dx} = \dfrac{\sqrt{1 - y^{2}}}{dy}\)
\(\displaystyle \dfrac{2dy }{(1 - y^{2})^{1/2}} = x^{-1/2}dx \)
\(\displaystyle 2\int \dfrac{dy}{(1 - y^{2})^{1/2}} = \int x^{-1/2}dx\) Did the 2 on the far left side come from substitution?
\(\displaystyle 2 \arcsin y + C_y = 2x^{1/2} + C_x\)
\(\displaystyle 2 \arcsin y + C_y - C_y - = 2x^{1/2} + C_x - C_y\)
\(\displaystyle 2 \arcsin y = 2x^{1/2} + C\)
\(\displaystyle \arcsin y = x^{1/2} + C\)
\(\displaystyle y = \sin(\sqrt{x} + C)\)
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