Any other way to represent (1+i)^(-n)

DexterOnline

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The discount factor or present value of dollar = (1+i)^(-n)

Is there any other representation of the above said formula?
 
The discount factor or present value of dollar = (1+i)^(-n)

Is there any other representation of the above said formula?
Well, if you really want to do it another way
The discount factor or present value of dollar = sin{-(-1)1/2 ln[(-1)1/2 x + (1-x2)1/2]} where x = (1+i)-n
 
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Well, if you really want to do it another way
The discount factor or present value of dollar = sin{-(-1)1/2 ln[(-1)1/2 x + (1-x2)1/2]} where x = (1+i)-n

All praise to the \(\displaystyle \left(-1\right)^{\frac{1}{2}}\) Lord who forgiveth all \(\displaystyle sin\)es not to mention the \(\displaystyle cos\)ines and if you were to go on a \(\displaystyle tan\)gent then it be heads up with \(\displaystyle \frac{sines}{cosines}\)
 
All praise to the \(\displaystyle \left(-1\right)^{\frac{1}{2}}\) Lord who forgiveth all \(\displaystyle sin\)es not to mention the \(\displaystyle cos\)ines and if you were to go on a \(\displaystyle tan\)gent then it be heads up with \(\displaystyle \frac{sines}{cosines}\)

Sines of the Times
 
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