C cmnalo Junior Member Joined Nov 5, 2006 Messages 61 Nov 13, 2006 #1 Find the inflection point, if any, for: g(t) = -t^2 + 4t + 4 g'(x) = -2t + 4 g"(x) = -2 How do you find the inflection point when there is no "x" in the second derivative?
Find the inflection point, if any, for: g(t) = -t^2 + 4t + 4 g'(x) = -2t + 4 g"(x) = -2 How do you find the inflection point when there is no "x" in the second derivative?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Nov 13, 2006 #2 That means there are none. f(x) is concave down on the entire interval \(\displaystyle (-\infty,+\infty)\) There are no changes in concavity.
That means there are none. f(x) is concave down on the entire interval \(\displaystyle (-\infty,+\infty)\) There are no changes in concavity.
