How to find first five positive values of the inverse circular relations: arccos 0.9 arccos (-0.2)
C cooldude New member Joined Oct 9, 2011 Messages 2 Oct 9, 2011 #1 How to find first five positive values of the inverse circular relations: arccos 0.9 arccos (-0.2)
D Deleted member 4993 Guest Oct 9, 2011 #2 cooldude said: How to find first five positive values of the inverse circular relations: arccos 0.9 arccos (-0.2) Click to expand... Using calculator! and Using the relationship: cos(Θ) = cos(2π ± Θ) Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
cooldude said: How to find first five positive values of the inverse circular relations: arccos 0.9 arccos (-0.2) Click to expand... Using calculator! and Using the relationship: cos(Θ) = cos(2π ± Θ) Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
