asa triangle -trig

musicman

New member
Joined
Jan 8, 2006
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2
i need help setting this one up!

" Radio direction finders are placed a points A and B, which are 3.46 miles apart on an east-west line, with A west of B. From A the bearing of a certain radio transmitter is 47.7degrees, and from B the bearing is 302.5degrees. find the distance of the transmitter from A."

please help.
 
It always helps to have a picture:

radiotransmitter7lr.gif



Angle A=90-47.7=42.3 degrees

Angle B=302.5-270=32.5 degrees

Angle C=180-(32.5+42.3)=105.2

Now, use the law of sines:

\(\displaystyle \frac{sinC}{c}=\frac{sinB}{b}\)

\(\displaystyle \frac{sin(105.2)}{3.46}=\frac{sin(32.5)}{b}\)

Solve for b.
 
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