M mathhelp New member Joined Nov 12, 2006 Messages 25 Nov 15, 2006 #1 Find the horizontal asymptote (left and right) of f(x) = 3 / (e^(-1x) - 6). Thank you for your time.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Nov 15, 2006 #2 Check your limits: \(\displaystyle \L\\\lim_{x\to\infty}\frac{3}{e^{-x}-6}\) \(\displaystyle \L\\\lim_{x\to-\infty}\frac{3}{e^{-x}-6}\)
Check your limits: \(\displaystyle \L\\\lim_{x\to\infty}\frac{3}{e^{-x}-6}\) \(\displaystyle \L\\\lim_{x\to-\infty}\frac{3}{e^{-x}-6}\)
