J jillpil87 New member Joined Oct 10, 2006 Messages 4 Oct 10, 2006 #1 How exactly would I go about doing these?: 1) Given f(x) = 2x - x^2, compute the average rate of change from 2 to x, for f(x). 2) Use the result from the previous problem to compute the average rate of change from x = 2 to x = 4. :?
How exactly would I go about doing these?: 1) Given f(x) = 2x - x^2, compute the average rate of change from 2 to x, for f(x). 2) Use the result from the previous problem to compute the average rate of change from x = 2 to x = 4. :?
D daon Senior Member Joined Jan 27, 2006 Messages 1,284 Oct 10, 2006 #2 Re: Average rate of change...I need help ASAP jillpil87 said: How exactly would I go about doing these?: Given f(x)=2x-x^2, compute the average rate of change from 2 to x, for f(x). Use the result from the previous problem to compute the average rate of change from x=2 to x=4. :? Click to expand... Average rate of change from a to b := \(\displaystyle \frac{f(b)-f(a)}{b-a}\) You have \(\displaystyle \frac{f(x)-f(2)}{x-2}=\frac{(2x-x^2)-0}{x-2}=\frac{x(2-x)}{x-2}=\frac{-x(x-2)}{x-2}=-x\)
Re: Average rate of change...I need help ASAP jillpil87 said: How exactly would I go about doing these?: Given f(x)=2x-x^2, compute the average rate of change from 2 to x, for f(x). Use the result from the previous problem to compute the average rate of change from x=2 to x=4. :? Click to expand... Average rate of change from a to b := \(\displaystyle \frac{f(b)-f(a)}{b-a}\) You have \(\displaystyle \frac{f(x)-f(2)}{x-2}=\frac{(2x-x^2)-0}{x-2}=\frac{x(2-x)}{x-2}=\frac{-x(x-2)}{x-2}=-x\)
