If ax[sup:10iaikbo]2[/sup:10iaikbo] + bx + 8 = (3x + 2)(x + k), find the values of a, b, and k.
This is supposed to be my practice question, and I only know that the final answer is a=3, b=14 and k=4
Thanks in advance! I'm in secondary 2 this year.
OK I just read the forum rules and I realise I need to write out the steps I did.
ax^2+bx+8=(3x+2)(x+k)
ax^2+bx+8=3x^2+3kx+2x+2k
ax^2+bx+8-(3x^2+3kx+2x+2k)=0
ax^2+bx+8-3x^2-3kx-2x-2k=0
-3x^2-2x+8=ax^2-bx+3kx+2k
(-3x+4)(x+2)=-x(ax-b)+k(3x+2)
I don't seem to be anywhere close to the solution, what am I supposed to do? Thanks
This is supposed to be my practice question, and I only know that the final answer is a=3, b=14 and k=4
Thanks in advance! I'm in secondary 2 this year.
OK I just read the forum rules and I realise I need to write out the steps I did.
ax^2+bx+8=(3x+2)(x+k)
ax^2+bx+8=3x^2+3kx+2x+2k
ax^2+bx+8-(3x^2+3kx+2x+2k)=0
ax^2+bx+8-3x^2-3kx-2x-2k=0
-3x^2-2x+8=ax^2-bx+3kx+2k
(-3x+4)(x+2)=-x(ax-b)+k(3x+2)
I don't seem to be anywhere close to the solution, what am I supposed to do? Thanks