Base 9 coordinate system (and an attempt at solving pi)

Michaelsrk

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Jan 9, 2017
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First off this is continued work from my "numbers without zero" thread. Except now I have found out how to define zero. Unfortunately in order to keep my theory concise I need to include some info from that post.

Circle%20-%202.jpg

If you take notice, all numbers corresponding to each other = 9 (1+8=9 )(2+7=9) (3+6=9)(4+5=9) then reverse (5+4=9)(6+3=9)(7+2=9)(8+1=9)
So I thought what if I make a graph using this idea, Here is what I came up with: edit: my girlfriend made me realize I was missing a column ignore the first image.


old:
ENamDw.png




New



ZxcqrG.png

If you will notice, all I simply did was write 123456789 and then in then next column I again wrote 012345678 As you can see the numbers split apart but always combine to 9

I also believe this little square is a growth rate
F72OhW.png
Unfortunately this is a hand drawn grid. a proper grid would result in a much nicer shape. Also does this seem to be a 2d version of how quantum mechanics work?

So I decided to try some algebra(I am not very good at it. based on this system using Pi(I previously used radians which I think I added wrong I will go back and look soon)
I am experimenting with removing the decimal point and the number to the right of it and also just removing the decimal point.

(deleted decimal point and the number to the right of it.)
even on both sides.
pi/1=(8) + 1/pi=(7) (6)
pi/2=(3) + 2/pi=(5) (8)
pi/3=(8) + 3/pi=(1) (9)
pi/4=(2) + 4/pi=(8) (1)
pi/5=(7) + 5/pi=(6) (4)
pi/6=(4) + 6/pi=(4) (8)
pi/7=(4) + 7/pi=(3) (7)
pi/8=(2) + 8/pi=(7) (9)
pi/9=(9) + 9/pi=(5) (4)
equal 9 on both sides.
pi/9=(9) + 0/pi = (0) (9)
pi/8=(2) + 1/pi = (7) (9)
pi/7=(4) + 2/pi = (5) (9)
pi/6=(4) + 3/pi = (2) (6)
pi/5=(7) + 4/pi = (8) (6)
pi/4=(2) + 5/pi = (6) (8)
pi/3=(8) + 6/pi = (4) (3)
pi/2=(3) + 7/pi = (3) (6)
pi/1=(8) + 1/pi = (7) (6)
pi/9=(9) + 0/pi = (0) (9)

deleted decimal point and the number to the right of it.
(even on both sides)
pi/1=(8) + 1/pi=(7) (6)
pi/2=(3) + 2/pi=(5) (8)
pi/3=(8) + 3/pi=(1) (9)
pi/4=(2) + 4/pi=(8) (1)
pi/5=(7) + 5/pi=(6) (4)
pi/6=(4) + 6/pi=(4) (8)
pi/7=(4) + 7/pi=(3) (7)
pi/8=(2) + 8/pi=(7) (9)
pi/9=(9) + 9/pi=(5) (4)

just deleted the decimal point.
equal 9 on both sides.
pi/9=(9) + 0/pi = (0) (9)
pi/8=(2) + 1/pi = (7) (9)
pi/7=(4) + 2/pi = (5) (9)
pi/6=(4) + 3/pi = (2) (6)
pi/5=(7) + 4/pi = (8) (6)
pi/4=(2) + 5/pi = (6) (8)
pi/3=(8) + 6/pi = (4) (3)
pi/2=(3) + 7/pi = (3) (6)
pi/1=(8) + 1/pi = (7) (6)
pi/9=(9) + 0/pi = (0) (9)
patterns 9
pi/9=(9) + 0/pi = (0) (9)
pi/7=(4) + 2/pi = (5) (9)
pi/8=(2) + 1/pi = (7) (9)
pi/9=(9) + 0/pi = (0) (9)
patterns 6
pi/1=(8) + 1/pi = (7) (6)
pi/2=(3) + 7/pi = (3) (6)
pi/5=(7) + 4/pi = (8) (6)
pi/6=(4) + 3/pi = (2) (6)

(even on both sides)
pi/9=(9) + 9/pi(7) (6)
pi/8=(2) + 8/pi(9) (2)
pi/7=(4) + 7/pi(3) (7)
pi/6=(4) + 3/pi(2) (6)
pi/5=(7) + 5/pi(7) (5)
pi/4=(2) + 4/pi(9) (2)
pi/3=(9) + 3/pi(2) (2)
pi/2=(4) + 2/pi(5) (9)
pi/1=(8) + 1/pi(7) (6)

6 pattern
pi/1=(8) + 1/pi(7) (6)
pi/6=(4) + 3/pi(2) (6)
pi/9=(9) + 9/pi(7) (6)
2 pattern
pi/3=(9) + 3/pi(2) (2)
pi/4=(2) + 4/pi(9) (2)
pi/8=(2) + 8/pi(9) (2)

if 1=5 2=6 ?

Am I doing this right? It's taking me along time to calculate this and I have only done addition.




My understanding of a "paradox"
Basically my understanding of a paradox is 2 mirrors placed on either side and viewing it from the center. The idea is that everything mimics everything in a parallel manor. More easily put, put your hands together and open them equally, You will see the same thing happening except your hands will mirror one another.
 
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