S sunnyandzorro New member Joined Jun 25, 2015 Messages 2 Jun 25, 2015 #1 Verify that every member of the family of functions y = A sin(5/2t) + B cos(5/2t) is a solution to 4y" = -25y I attached my crappy work so you can see where I am getting stuck... what am I getting wrong? Thanks Attachments problem.jpg 249.6 KB · Views: 1
Verify that every member of the family of functions y = A sin(5/2t) + B cos(5/2t) is a solution to 4y" = -25y I attached my crappy work so you can see where I am getting stuck... what am I getting wrong? Thanks
D Deleted member 4993 Guest Jun 25, 2015 #2 sunnyandzorro said: Verify that every member of the family of functions y = A sin(5/2t) + B cos(5/2t) is a solution to 4y" = -25y I attached my crappy work so you can see where I am getting stuck... what am I getting wrong? Thanks Click to expand... y' = A(5/2)cos(5t/2) - B(5/2)sin(5t/2) y" = -A(25/4)sin(5t/2) - A(25/4)cos(5t/2)
sunnyandzorro said: Verify that every member of the family of functions y = A sin(5/2t) + B cos(5/2t) is a solution to 4y" = -25y I attached my crappy work so you can see where I am getting stuck... what am I getting wrong? Thanks Click to expand... y' = A(5/2)cos(5t/2) - B(5/2)sin(5t/2) y" = -A(25/4)sin(5t/2) - A(25/4)cos(5t/2)
S sunnyandzorro New member Joined Jun 25, 2015 Messages 2 Jun 25, 2015 #3 Thanks, I knew it was something silly!