bearings + trigonometry

willow (she/her)

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Jan 19, 2021
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hi i'm doing a question that combines bearings and sine/cosine rule. i'm so confused on how to work it out so help would be appreciated!!

P, Q and R are three points on a map.
Q is 47km and on a bearing of 055degrees from P.
R is 79km and on a bearing of 159degrees from Q
Calculate the distance between P and R rounded to 1 DP.


my main problem is i have no idea how to construct the triangle because i find bearings confusing.
my attempt (which is probably wrong) :(
159-55=104 which is the angle at Q in the triangle
so then using the cosine rule
a2=472+792-2 x 47 x 79 x cos(104)
a2=10246.512
and then square root to get a/ PR = 101.2km (1DP)
 
Your answer is correct. Do you want any more help?
 
Last edited:
One thing to get squared away from the start is what sort of bearings are we talking about.

(Aero)Nautical bearings have 0 degrees due north and increase as you move clockwise through east, south, west.

Everyone else uses bearings that have 0 degrees due east and increase as you move counter clockwise through north, west, south.

When I hear the word "bearings" I usually think of Nautical bearings.
Hi so I think it's referring to Nautical bearings.
 
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