Binomial probability help

hollicrombie&stitch

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Joined
Mar 20, 2020
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Hi, having some trouble with this binomial probability question. Not too hard, I think I'm just missing a case or something.
"A man is restoring ten old cars, six of them manufactured in 1955 and four of them manufactured in 1962. When he tries to start them, on average the 1955 models will start 65% of the time and the 1962 models will start 80% of the time. Find the probability that at any time exactly three of the 1955 models and one of the 1962 models will start."
I did 6C3*0.653*0.353 + 4C1*0.8*0.23 but it didn't work. Answer is 0.006
Thanks!
 
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