Calc 3: find equation in space?

whig4life

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Suppose a, b are two positive numbers. Find an equation for the line in space
passing through "a" on the x-axis and "b" on the y-axis.

Show steps and explain how you arrived at this.
 
Do you know the "Intercept Form"?

xa+yb=1\displaystyle \frac{x}{a} + \frac{y}{b} = 1

Done.
 
Suppose a, b are two positive numbers. Find an equation for the line in space
passing through "a" on the x-axis and "b" on the y-axis.

Show steps and explain how you arrived at this.
A line can be written in a variety of ways: y= mx+ b, Ax+ By= 1, x= py+ q, etc. Each of those involves two coefficients that you need to find. You need two equations to find two values.

Every point on the x-axis has y value 0 and every point on the y- axis has x value 0 so saying the line passes "through "a" on the x-axis and "b" on the y-axis" means that x= a, y= 0 and x= 0, y= b satisfy the equation. Choose any one of the forms above, set x= a, y= 0 in it to get one equation, set x= 0 y= b in it to get another equation, and solve for the coefficients.
 
Hello, whig4life!

Did I interpret the question correctly?


Suppose a,b\displaystyle a, b are two positive numbers.
Find an equation for the line in space
passing through a\displaystyle a on the x-axis and b\displaystyle b on the y-axis.

Show steps and explain how you arrived at this.

The x-intercept is A(a,0,0)\displaystyle A(a,0,0)
The y-intercept is B(0,b,0)\displaystyle B(0,b,0)

The vector v=AB=-a,b,0\displaystyle \vec v \:=\:\overrightarrow{AB} \:=\:\langle \text{-}a,b,0\rangle


The line through (a,0,0)\displaystyle (a,0,0) with direction vector v=-a,b,0\displaystyle \vec v \:=\:\langle \text{-}a,b,0\rangle

. . . has the parametric equations: .{x=aaty=btz=0}\displaystyle \begin{Bmatrix}x \:=\: a-at \\ y \:=\: bt \\ z \:=\: 0 \end{Bmatrix}
 
Hi whig.

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