NameisJames
New member
- Joined
- Jun 11, 2022
- Messages
- 1
find the arclength for 0<= t <= 1/2pi of the curve (cos 2t + 3,7 - sin 2t)
Please show us what you have tried and exactly where you are stuck.find the arclength for 0<= t <= 1/2pi of the curve (cos 2t + 3,7 - sin 2t)
Tutors please note that the OP has not posted any work, neither did s/he answer the questions posed by StevenG.\(\displaystyle x = \cos 2t + 3\)
\(\displaystyle y = 7 - \sin 2t\)
Arc length \(\displaystyle = \int_{0}^{\pi/2} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \ dt\)
I personally like doing a problem at the lowest level possible. Right or wrong this is my style.\(\displaystyle x = \cos 2t + 3\)
\(\displaystyle y = 7 - \sin 2t\)
Arc length \(\displaystyle = \int_{0}^{\pi/2} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \ dt\)
Only the formula was given, is that so bad? Or possibly you removed some posts??Tutors please note that the OP has not posted any work, neither did s/he answer the questions posed by StevenG.
Your approach works fine. I just used the calculus way to solve the problem.I personally like doing a problem at the lowest level possible. Right or wrong this is my style.
You should immediately see that this is a circle. I actually drew the circle and the the answer was then obvious after considering the domain.