
This is my effort in solving the problem.

Here is my work:
SQR=44° (>s in alternate segment)
PSR=PSQ+QSR
SQR=QSR=44° (base >s of an isosceles triangle)
QRS=180−(2×44)=92° (sum of >s in a triangle )
QRS=QPS=92° (opposite >s of a cyclic quadrilateral)
PSQ=180−(92+31)=57°
Since PSR=PSQ+QSR
PSR=57°+44°=101°
Is my solution correct?