Calculate the measure of the angle "x" - from "Puzzle Sphere" of "Medium"
- Thread starter khansaheb
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Dr.Peterson
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I've seen it in many places. There's a very different solution based on constructing a regular polygon around vertex A (S in my version):
Most of this is easy once you see the idea; the hard part is to explain concisely why T and U both lie on RF (which is the reflection of BN actoss diameter AJ, and of DP across diameter BK, which contain U and T respectively).
Most of this is easy once you see the idea; the hard part is to explain concisely why T and U both lie on RF (which is the reflection of BN actoss diameter AJ, and of DP across diameter BK, which contain U and T respectively).