For less than and less than or equal to I know how to do it, but for "greater than (>)" and "equal to" unfortunately not. We have to do this with the normCDF or normPDF, so I ask the helper to refer ONLY to this formula.
No. 1 with continuity correction; µ = 120, σ = 10
a) P(X<120) = normCDF (-∞;119.5;120;10) = 0.4801
b) P(X<=120) = normCDF (-∞;120.5;120;10) = 0.5199
c) P(110<=X<=130) = normCDF (109.5;130.5;120;10) = 0.7063
d) P(X=14) = ??
e) P(X>120) = ??
f) P(X>=120) = ??
No. 2 without continuity correction (i.e. normally distributed); µ = 120, σ = 10
a) P(X<120) = normCDF (-∞;120;120;10) = 0.5
b) P(X<=120) = normCDF (-∞;120;120;10) = 0.5
c) P(110<=X<=130) = normCDF (110;130;120;10) = 0.683
d) P(X=14) = ??
e) P(X>120) = ??
f) P(X>=120) = ??
Any help is appreciated and sorry if terms come up that you haven't heard of (English isn't my first language).
No. 1 with continuity correction; µ = 120, σ = 10
a) P(X<120) = normCDF (-∞;119.5;120;10) = 0.4801
b) P(X<=120) = normCDF (-∞;120.5;120;10) = 0.5199
c) P(110<=X<=130) = normCDF (109.5;130.5;120;10) = 0.7063
d) P(X=14) = ??
e) P(X>120) = ??
f) P(X>=120) = ??
No. 2 without continuity correction (i.e. normally distributed); µ = 120, σ = 10
a) P(X<120) = normCDF (-∞;120;120;10) = 0.5
b) P(X<=120) = normCDF (-∞;120;120;10) = 0.5
c) P(110<=X<=130) = normCDF (110;130;120;10) = 0.683
d) P(X=14) = ??
e) P(X>120) = ??
f) P(X>=120) = ??
Any help is appreciated and sorry if terms come up that you haven't heard of (English isn't my first language).