A Andyii New member Joined May 2, 2022 Messages 1 May 2, 2022 #1 Hello, could anyone help me solve or give a general idea on where to start with this function? The answer is supposed to be a/m - b/n but I'm not quite sure how to get there.
Hello, could anyone help me solve or give a general idea on where to start with this function? The answer is supposed to be a/m - b/n but I'm not quite sure how to get there.
D Deleted member 4993 Guest May 2, 2022 #2 Andyii said: Hello, could anyone help me solve or give a general idea on where to start with this function? The answer is supposed to be a/m - b/n but I'm not quite sure how to get there. View attachment 32519 Click to expand... Andyii said: The answer is supposed to be a/m - b/n but I'm not quite sure how to get there. Click to expand... Where did these 'a' and 'b' come from? I have a strong suspicion, but need to hear from you. Do you know L'Hopital's rule? And: Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem
Andyii said: Hello, could anyone help me solve or give a general idea on where to start with this function? The answer is supposed to be a/m - b/n but I'm not quite sure how to get there. View attachment 32519 Click to expand... Andyii said: The answer is supposed to be a/m - b/n but I'm not quite sure how to get there. Click to expand... Where did these 'a' and 'b' come from? I have a strong suspicion, but need to hear from you. Do you know L'Hopital's rule? And: Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem
blamocur Elite Member Joined Oct 30, 2021 Messages 3,222 May 2, 2022 #3 A hint: you might find this helpful: [math]\sqrt[m]{1+ax} - \sqrt[n]{1+bx} = \left( \sqrt[m]{1+ax} - 1 \right) - \left( \sqrt[n]{1+bx} - 1 \right)[/math]
A hint: you might find this helpful: [math]\sqrt[m]{1+ax} - \sqrt[n]{1+bx} = \left( \sqrt[m]{1+ax} - 1 \right) - \left( \sqrt[n]{1+bx} - 1 \right)[/math]