A andy849 New member Joined Jan 31, 2010 Messages 4 Apr 6, 2013 #1 determine the limit (don't use L'Hospital's Rule) limit (1-cos(2x))/(X^2) as x->0 i'm not sure what to do? do i have to substituted 1-cos(2x) for something
determine the limit (don't use L'Hospital's Rule) limit (1-cos(2x))/(X^2) as x->0 i'm not sure what to do? do i have to substituted 1-cos(2x) for something
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Apr 6, 2013 #2 Good guess, but not quite. Just get the cosine. \(\displaystyle \cos(2x) = 1 - 2\sin^{2}(x)\) Last edited: Apr 6, 2013
