Calculus Help!

[ezravg]

The period T (in seconds) of a pendulum is T= 2pi*radical(L/32), where L is measured in feet. If 2 ft ​< L < 8 ft, what is the
range in T?

 

[stapel]

The period T (in seconds) of a pendulum is T= 2pi*radical(L/32), where L is measured in feet. If 2 ft ​< L < 8 ft, what is the range in T?

You are given a relationship between T and L. You are give an interval of values for L. You are asked for the corresponding interval of values for T.

What did you get when you graphed T(L) over the given interval, the way you learned back in algebra? What did you conclude when you considered the nature of the square-root function? Where are you stuck?

Please be complete. Thank you!