can anyone give me some problems so that i can practice?

A

abel muroi

Junior Member
Joined
Jan 13, 2015
Messages
210
I need someone to give me 3 problems on circles, 3 on linear functions, and 3 on quadratic functions

this is for a test that i will be taking tomorrow, so i need to practice.
 
abel muroi said:
I need someone to give me 3 problems on circles, 3 on linear functions, and 3 on quadratic functions

this is for a test that i will be taking tomorrow, so i need to practice.
Click to expand...
Find the eq of the circle whose center is at (3,-1) and has a radius of 4.
Find the eq of the circle whose center is at (5,2) and has a radius of -6.

Find the center and radius for the circle x^2 - 4x +y^2 +2y =0

Find the equation of the line that is parallel to 2x-3y =6 and passes through the point (1,8)
Find the equation of the line that is perpendicular to 4x-2y =6 and passes through the point (2,3)
Find the eq of the line whose slope is 3/4 and passes through the point (2, pi)
 
Last edited:
Jomo said:
Find the eq of the circle whose center is at (3,-1) and has a radius of 4.
Find the eq of the circle whose center is at (5,2) and has a radius of -6.

Find the center and radius for the circle x^2 - 4x +y^2 +2y =0

Find the equation of the line that is parallel to 2x-3y =6 and passes through the point (1,8)
Find the equation of the line that is perpendicular to 4x-2y =6 and passes through the point (2,3)
Find the eq of the line whose slope is 3/4 and passes through the point (2, pi)
Click to expand...

Find the eq of the circle whose center is at (3,-1) and has a radius of 4.

(x-3)2 + (y+1)2 = 16

Find the eq of the circle whose center is at (5,2) and has a radius of -6

I never really got a circle with a negative radius before but this is my best try at making the equation

(y - 5)2 + (y - 2)2 = 36

Find the center and radius for the circle x^2 - 4x +y^2 +2y =0

(x + 2)2 + (y - 1)2 = 25

center is (-2, 1)

radius = 5

Find the equation of the line that is parallel to 2x-3y =6 and passes through the point (1,8)

y = 2/3x - 22/3


 Find the equation of the line that is perpendicular to 4x-2y =6 and passes through the point (2,3)

y = -1/2x + 4
 
abel muroi said:
Find the eq of the circle whose center is at (3,-1) and has a radius of 4.

(x-3)2 + (y+1)2 = 16 CORRECT

Find the eq of the circle whose center is at (5,2) and has a radius of -6

I never really got a circle with a negative radius before but this is my best try at making the equation

(y - 5)2 + (y - 2)2 = 36 THE RADIUS CAN NEVER BE NEGATIVE SO THERE IS NO EQUATION. hOW CAN THE DISTANCE FROMM THE CENTER OF THE CIRCLE TO A POINT ON THE CIRCLE BE NEGATIVE?

Find the center and radius for the circle x^2 - 4x +y^2 +2y =0

(x + 2)2 + (y - 1)2 = 25 YOU NEED TO KEEP THE SIGN OF THE COEFFICIENT OF THE X AND Y TERM. i AM FAIRLY SURE THAT YOU KNOW THAT YOU ADDED 5 TO THE LEFT SIDE BUT THEN ADDED 25 TO THE RIGHT SIDE! WHY, BECAUSE THE SQRT OF 25 IS 5?

center is (-2, 1)

radius = 5

Find the equation of the line that is parallel to 2x-3y =6 and passes through the point (1,8)

y = 2/3x - 22/3 NO. 2/3 - 22/3 IS NOT 8


 Find the equation of the line that is perpendicular to 4x-2y =6 and passes through the point (2,3)

y = -1/2x + 4 CORRECT
Click to expand...
I would give this work a score of 70%, which is passing. I would give 1/2 credit on the ones you did not get correct
 
Jomo said:
I would give this work a score of 70%, which is passing. I would give 1/2 credit on the ones you did not get correct
Click to expand...

so for the equation of the parallel line problem you gave me, is the equation actually y = 2/3x + 22/3?

and for the problem you gave that asked me to find radius and center..

should the equation be (x + 2)2 + (y - 1)2 = 25 or (x - 2)2 + (y + 1)2 = 25 ?

btw did i even get the correct radius?
 
abel muroi said:
so for the equation of the parallel line problem you gave me, is the equation actually y = 2/3x + 22/3? correct

and for the problem you gave that asked me to find radius and center..

should the equation be (x + 2)2 + (y - 1)2 = 25 or (x - 2)2 + (y + 1)2 = 25 ?

btw did i even get the correct radius?
Click to expand...
Abel, multiply (x + 2)2 + (y - 1)2 and (x - 2)2 + (y + 1)2 yourself to see which is correct.
This is the second time that I asked how you got 25.
 
You must log in or register to reply here.
Top