can anyone help me to convert parametric to cartesian equation?

[Klaudia Ndreca]

y=-2 sin(π×t÷3)-3
x=-4cos(π×t÷3)

 

[Deleted member 4993]

y=-2 sin(π×t÷3)-3
x=-4cos(π×t÷3)

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment.

hint:

y=-2 sin(π×t÷3)-3 .........convert to............ (y+3)/2=- sin(π×t÷3)

and

x=-4cos(π×t÷3)\(\displaystyle \ \ \to \ \ \ \)x/4=-cos(π×t÷3)

 

[Klaudia Ndreca]

i wanted to convert and to find the graph.. hmm i think it is an ellipse. thank you

 

[tkhunny]

"I think" is a poor determination. Either it is or it isn't.

Please specify the ellipse if that's truly what it is. Center? Vertices? Major and minor axes? Eccentricity? Go!

 

[Klaudia Ndreca]

This task is in rational mechanics. And i wanted to know what graph does this equation have?

 

[HallsofIvy]

Do you know what \(\displaystyle sin^2\left(\frac{\pi}{3}t\right)+ cos^2\left(\frac{\pi}{3}t\right)\) is?

 

[Klaudia Ndreca]

sin2(πt/3)+cos2(πt/3)=1

 

[Deleted member 4993]

Do you know what \(\displaystyle sin^2\left(\frac{\pi}{3}t\right)+ cos^2\left(\frac{\pi}{3}t\right)\) is?

I think you mean:

sin^2(πt/3) + cos^2(πt/3) = 1

 

[Deleted member 4993]

sin^2(πt/3)+cos^2(πt/3)=1

If that is what you meant (which is correct) - now look at the response #2 again and think.....