can anyone tell me where I did wrong?[math]9^x-2^(x+0.5)=2^(x+3.5)-3^(2x-1)[/math]

[ALIAHMAD]

taking [math]2^x[/math]=a and [math]3^x[/math]=b

now the equation becomes [math]b^2-a√2 =8a√2-b^2/3[/math]

 

[ALIAHMAD]

sorry just realised while writing question what I did wrong
can anyone tell me how to delete this thread?

 

[Steven G]

You can't delete the thread.

 

[BigBeachBanana]

sorry just realised while writing question what I did wrong
can anyone tell me how to delete this thread?

You can share your solution. Someone might benefit from it.

 

[lookagain]

now the equation becomes [math]b^2-a√2 =8a√2-b^2/3[/math]

If you post more threads, please do not put your equation in the title. Your equation,
In non-Latex, was really this:

9^x - 2^(x + 0.5) = 2^(x + 3.5) - 3^(2x - 1)

Then, after your substitutions, it would become the equation you wrote in post # 1.