G grapz Junior Member Joined Jan 13, 2007 Messages 80 Mar 2, 2008 #1 The only method i can think of is by guessing the answer to this equation. k - [ ( sin 2k ) / 2] = 5pi / 12 - 1/4 I guess the answer to be 5pi / 12 and it works
The only method i can think of is by guessing the answer to this equation. k - [ ( sin 2k ) / 2] = 5pi / 12 - 1/4 I guess the answer to be 5pi / 12 and it works
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Mar 3, 2008 #2 The 'k' term keeps it from having more than one solution. Various iterative techniques can be used to find a numeric solution.
The 'k' term keeps it from having more than one solution. Various iterative techniques can be used to find a numeric solution.
