can someone help me solve this inequality?

[icantsolveinequalities]

Hello guys, i find it very hard to solve this inequality.Can someone help me
[MATH](2-x)/(x^2-x-2) <= (2-x)/(x^2+x-2)[/MATH]

 

[pka]

Hello guys, i find it very hard to solve this inequality.Can someone help me
[MATH](2-x)/(x^2-x-2) <= (2-x)/(x^2+x-2)[/MATH]

I suggest rewriting as \(\dfrac{(x-2)}{(x-2)(x+1)}\ge\dfrac{(x-2)}{(x+2)(x-1)}\)

 

[Dr.Peterson]

Hello guys, i find it very hard to solve this inequality.Can someone help me
[MATH](2-x)/(x^2-x-2) <= (2-x)/(x^2+x-2)[/MATH]

There may be a special way to solve this one, but the standard approach is to subtract one side from the other, like

[MATH]\dfrac{(x-2)}{(x-2)(x+1)} - \dfrac{(x-2)}{(x+2)(x-1)}\ge 0[/MATH]​

and then combine the fractions. Then you can work with factors to find when the LHS is positive or zero.