Thanks a lot!!To follow up, we find:
[MATH]r=\sqrt{\frac{3V}{\pi h}}[/MATH]
And so the obliquity is:
[MATH]\theta=\arctan\left(\frac{h}{r}\right)=\arctan\left(h\sqrt{\frac{\pi h}{3V}}\right)[/MATH]
Plugging in the given data, and converting to degrees, we find:
[MATH]\theta\approx11.35^{\circ}[/MATH]