Can't remember how to do this...(3/(x^2)) + (5/x) - 12=0

A

amyp

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Apr 30, 2009
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Hi there. I'm trying to help a friend with her math, but it's been a few years and I cannot remember how to solve these problems. (And I don't remember what it's called to look at examples and figure out how to do it)

Here are the problems she is supposed to solve:

(3/(x^2)) + (5/x) - 12=0

And...

(3/(x-1)) + (10/(x+1)) = 4

With this one I tried making a common denominator and then added like terms in the numerator but got lost trying to solve for x after that...

Thank you so much for the help!
 
One approach is to multiply both sides of the equation by the least common denominator.

\(\displaystyle \frac{3}{x^2}+ \frac{5}{x}- 12 = 0\)

\(\displaystyle \frac{3}{x^2}\cdot \frac{x^2}{1}+ \frac{5}{x}\cdot \frac{x^2}{1}- 12\cdot \frac{x^2}{1} = 0\cdot \frac{x^2}{1}\)

3 + 5x - 12x[sup:3n9vkprl]2[/sup:3n9vkprl] = 0

Can you take it from there?
 
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