Circles

supernova

New member
Joined
May 5, 2010
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4
Hey everyone. I'm new but I'd like some advice on where to start on solving the angle measures below. I've been trying to learn all the properties but I'm a little intimidated by this sheet. I appreciate the help in advance, and I apologize I can't show work. I have answers to solving for x; the first 26 is where I need help.

Scan_Pic0001.jpg
 
\(\displaystyle supernova, \ if \ you \ have \ a \ smattering \ of \ geometric \ properties, \ you \ should \ be \ able \ to\)

\(\displaystyle figure \ out \ all \ the \ answers. \ Is \ a \ the \ center \ of \ the \ circle? \ If \ so, \ a \ good \ starting \ point.\)
 
\(\displaystyle 1. \ 40^0\)

\(\displaystyle 2. \ 40^0\)

\(\displaystyle 3. \ 20^0\)

\(\displaystyle 4. \ 80^0\)

\(\displaystyle 5. \ 80^0\)

\(\displaystyle 6. \ 40^0\)

\(\displaystyle 7. \ 100^0\)

\(\displaystyle 8. \ 40^0\)

\(\displaystyle 9. \ 70^0\)

\(\displaystyle 10. \ 30^0\)

\(\displaystyle 11. \ 60^0\)

\(\displaystyle 12. \ 120^0\)

\(\displaystyle 13. \ 40^0\)

\(\displaystyle 14. \ 70^0\)

\(\displaystyle 15. \ 80^0\)

\(\displaystyle 16. \ 30^0\)

\(\displaystyle 17. \ 110^0\)

\(\displaystyle 18. \ 70^0\)

\(\displaystyle 19. \ 50^0\)

\(\displaystyle 20. \ 90^0\)

\(\displaystyle 21. \ 90^0\)

\(\displaystyle Here's \ what \ I \ got \ for \ the \ first \ 21. \ See \ if \ you \ get \ the \ same.\)
 
Looks good, Heavy; how do you explain Arc AF = 160 (integer)?
 
You can put degree sign by using <ALT><0176> (you'll need to use the "num" pad)

When you type 90<ALT><0176> you would get 90°.

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Thanks ever so much for the help. I had some courage and tried the entire sheet on my own and I'm proud to say I'm a little bit over 2/3 of the way done. Could somebody explain where to go from this point if I have the following correct answers? By the way, the order I solved for them is listed below; tell me if this is logical.

m<15 = 80 degrees; 160/2 = 80.
m<2 = 40 degrees; given
m<13 = 40 degees. arc AF = 160, arc BD = 80 (how do i know this?) -> 160-80=80 -> 80/2 = 40.
m<1 = 40; alt. interior angles
m<4 = 80 (why?)
m<7 = 100; m<7 + m<4 must add up to 180 degrees.
m<3 = 20; m<1 + m<2 + m<4 = 160, 180-160 = 20
m<5 = 80; central angle equals arc
m<6 = 40; property of geometry, forget name
m<8 = 40; m<7 + m<6 = 140, 180-140 = 40
m<20 = 90; by the triangle sum theorem, the triangle to the left of the triangle with <20 has a right angle; the right angle is adjacent to <20 and the two angles must add up to 180.
m<21 = 90; same reason as above
m<19 = 50; triangle sum theorem, m<20 + m<2 = 130, 180-130 = 50
m<11 = 60; by the triangle sum theorem, the vertical angle across from <11 equals 60.
m<12 = 120; linear pair postulate? <11 and <12 MUST add to 180, so 180-60 = 120.

Anyone want to show me where to go and to maybe explain some of the properties in my proof above? Much appreciated again guys.
 
Apology for the double post, but would anyone appreciate answering my question and parts of the sheet below? (I'll post it tomorrow evening)
 
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