college algebra

girlpower

New member
Joined
Aug 16, 2012
Messages
47
If a=/b and 1/x+1/a=1/b ,then x=? help meeee I haven't learned this that why I haven't shown in work
 
If a=/b and 1/x+1/a=1/b ,then x=? help meeee I haven't learned this that why I haven't shown in work
It seems clear to me that you have retained NOTHING that you ever learned in an Algebra class. A placement test will show that, and will allow the PTB to place you in an appropriate Beginning Algebra class. Don't get so uptight about it. Did you read the response by MrsPi to one of your earlier questions?

As to this question, did you even bother to look at it?

If it said: "A=B and (A+X)=B, what is X?", would that be any easier?

What is different when x is in the denominator?
 
If a=/b and 1/x+1/a=1/b ,then x=? help meeee I haven't learned this that why I haven't shown in work
You said in an earlier post that you were studying for a college placement exam. Stop worrying about that exam. You absolutely need a remedial math course. This question does not involve college-level math; it involves beginning algebra. If you take any course requiring knowledge of college-level math, you will fail it unless you take remedial math first.

Algebraic symbols are just numbers. You learned how to deal with numbers that are fractions in grade school.

If \(\displaystyle \dfrac{1}{x} = \dfrac{5}{12},\) what does x =?

If \(\displaystyle y + \dfrac{1}{4} = \dfrac{2}{3} \implies y = \dfrac{2}{3} - \dfrac{1}{4},\) what does y =?

So if \(\displaystyle \dfrac{1}{x} + \dfrac{1}{4} = \dfrac{2}{3},\) what does x =?
 
I am confuse to how you got for 1/x = 5/12 can you explain to me how you got this?
 
If a=/b and 1/x+1/a=1/b ,then x=? help meeee I haven't learned this that why I haven't shown in work
I suspect that "a=/ b" was supposed to be "a is not equal to b". To "solve an equation" in x means to change it to look like "x= ...". That is, to get x by itself on the left side. The first thing it should occur to you to do is subtract 1/a from both sides to get 1/x= 1/b- 1/a. You should know, from arithmetic, that is 1/x= p/q, then x/1= q/p.
So all you need to do now is do that subtraction on the right- get a "common denominator" and subtract numerators. Can you do that? What is the common denominator? Once you have done that, as I said, turn both fractions over:
x/1= x= what?

Do you see why a cannot be equal to b?
 
Top